Newton's Laws Legacy Problem #11 Guided Solution
Problem*
Ethan is dragging a bag of grass from the garage to the street on the evening before garbage pick-up day. The diagram at the right is a free-body diagram. It uses arrows to represent the forces acting upon the bag. Each force is labeled according to type. The magnitude of the force is represented by the size of the arrow. Use the free body diagram to determine the net force acting upon the bag. The values of the individual forces are:

\(F_\text{grav} = F_\text{norm} = 60.5 N\)
\(F_\text{app} = 40.2 N\)
$F_\text = 5.7 N $
Audio Guided Solution
The diagram that you see at the right is known as a free body diagram. It provides a visual representation of the forces, or the pushes or pulls, which act up on our bag of grass. Each force is represented by an arrow, and the arrow points in the direction of the force. Each arrow is labeled with a label that tells you what type of force it is. You can read more about these types of forces by using the link to the physics classroom that you see below this question. Now what we're to do here is determine the net force. The net force is simply the vector sum of all the forces. Meaning you simply add up all the force values, treating them as vectors which have a direction. When you add vectors, you add them differently than when you add scalars. For instance, 5 plus 5, to most of us, is equal to 10. But to the physics student, 5 plus 5 could be equal to 0. Or any other number that you could get when you add 5 plus 5 as vectors. It could be equal to 0 if the two 5's are going in opposite directions. You would treat 1 as negative and add it to the positive. So in this problem, we notice the Fgrav, that's gravity force, and the Fnorm, or normal force, are of the same size and going in opposite directions. So they would add up to 0. That leaves us with two more forces to add together. The applied force, F-amp, and the friction force, F-frict. We have to add these as vectors. One goes 40.2 newtons to the right, and the other 5.7 newtons to the left. So the way to add such vectors is to call the left one negative, and then add the negative value onto the positive right one. So you're going 40.2 plus negative 5.7.
Solution
34.5 N, right
Habbits of an Effective Problem Solver
- Read the problem carefully and develop a mental picture of the physical situation. If necessary, sketch a simple diagram of the physical situation to help you visualize it.
- Identify the known and unknown quantities in an organized manner. Equate given values to the symbols used to represent the corresponding quantity - e.g., \(v_o = \units{0}{\unitfrac{m}{s}}\); \(a = \units{4.2}{\unitfrac{m}{s^2}}\); \(v_f = \units{22.9}{\unitfrac{m}{s}}\); \(d = \colorbox{gray}{Unknown}\).
- Use physics formulas and conceptual reasoning to plot a strategy for solving for the unknown quantity.
- Identify the appropriate formula(s) to use.
- Perform substitutions and algebraic manipulations in order to solve for the unknown quantity.
Read About It!
Get more information on the topic of Newton's Laws at The Physics Classroom Tutorial.