Work and Energy Legacy Problem #7 Guided Solution

Here we are told that the mechanical arm on a conveyor system exerts a force of 800 Newtons upon a crate to move it 12 meters in 22 seconds. What we have is a picture of a force doing work upon a crate, and we are given the time that it takes to do a specific amount of work, or at least the time it takes to apply a force and move it a given distance. Now when I look at a physics problem like this, having a good understanding of conceptual ideas and mathematical relationships helps me to get from the givens to the unknown quantity quite quickly. I understand power to be a ratio of work over time, and I understand work to be a force multiplied by distance. Since I am given the force of 890 Newtons and the distance of 12 meters, I will be able to calculate the work done upon this crate by this mechanical arm. I go W equals Fd, and I use 890 Newtons as F and 12 meters as D. I get 10,680 Joules of work being done. This work is done in 22 seconds, so to find the power, take the ratio of work to time. I take this 10,680 Joules and divide it by 22 seconds. That gives me 485.45 as my power. I can round that to 490 for two significant digits, and Watt is the unit of power. I didn't mean to ask Watt is the unit of power, I meant to say Watt is the unit of power. Let's try it again. How about, and the unit of power is the Watt? That still sounds like a question. The unit Watt, yeah, Watt, W-A-T-T, not Watt, W-H-A-T, but Watt, W-A-T-T, that's the unit of power. I need to take a break.